Solve for \( x \) using the square root property. \( p^{2}=9 \) \( p=\square \) Basic Funcs Trig

To solve for \( p \) using the square root property, we start by taking the square root of both sides of the equation \( p^{2} = 9 \). This gives us: \[ p = \sqrt{9} \quad \text{or} \quad p = -\sqrt{9} \] Calculating the square roots, we find: \[ p = 3 \quad \text{or} \quad p = -3 \] Thus, the solutions are \( p = 3 \) and \( p = -3 \). Now you have your values of \( p \) in hand; whether you're working on geometry problems or physics equations, those values can pop up quite a bit! For instance, in quadratic functions, understanding how to leverage properties like this can lead to quick solutions without the tedious need for factoring or completing the square. Additionally, when dealing with equations that involve squares, a common mistake is forgetting the negative root, which can leave you with incomplete solutions. Always remember that for equations of the form \( p^2 = k \), both positive and negative solutions are valid. So when you're in a crunch, double-check for both possibilities!