Pregunta
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Mary gave one third of her moncy to Nazeem and one fifth of her money to Elwethu. Elwethu received R28 less than Nazcem. How much money did Mary have originally?

Ask by Ward Maxwell. in South Africa
Mar 18,2025

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Mary originally had R210.

Solución

Let \( x \) be the amount of money Mary had originally. 1. Mary gave \(\frac{x}{3}\) to Nazeem and \(\frac{x}{5}\) to Elwethu. 2. According to the problem, Elwethu received \(28\) rands less than Nazeem, so: \[ \frac{x}{3} - \frac{x}{5} = 28 \] 3. Find a common denominator for the fractions (which is \(15\)): \[ \frac{5x}{15} - \frac{3x}{15} = \frac{2x}{15} = 28 \] 4. Solve for \( x \) by multiplying both sides by \(15\): \[ 2x = 28 \times 15 = 420 \] 5. Divide both sides by \(2\) to find \( x \): \[ x = \frac{420}{2} = 210 \] Mary originally had R\(210\).

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The Deep Dive

Let's break this down in a fun way! If Mary gave one third of her money to Nazeem, we can represent this as \( \frac{1}{3}M \) and to Elwethu as \( \frac{1}{5}M \). According to the information given, Elwethu received R28 less than Nazeem. So, we have \( \frac{1}{5}M = \frac{1}{3}M - 28 \). By solving this equation, we can find out Mary's original amount of money, which turns out to be R420! Now, isn’t it amusing how such a riddle-like problem can make us apply our math skills? It's like solving a mystery with numbers! Certainly, practicing problems like this can help sharpen your problem-solving abilities and prepare you for even trickier challenges ahead!

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