Pregunta
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\( \left. \begin{array} { l } { ( 2 x - 3 ) ( 3 x + 2 ) = } \\ { ( 2 x - 3 ) ( 2 x + 1 ) = } \\ { ( 3 x - 2 ) ( 2 x + 3 ) = } \\ { ( 3 x - 2 ) ( 2 x - 3 ) = } \end{array} \right. \)

Ask by Stuart Mckenzie. in Malaysia
Mar 16,2025

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\[ \begin{align*} (2x - 3)(3x + 2) &= 6x^2 - 5x - 6 \\ (2x - 3)(2x + 1) &= 4x^2 - 4x - 3 \\ (3x - 2)(2x + 3) &= 6x^2 + 5x - 6 \\ (3x - 2)(2x - 3) &= 6x^2 - 13x + 6 \end{align*} \]

Solución

**1. Expanding \((2x-3)(3x+2)\):** - Multiply the first terms: \(\quad 2x \cdot 3x = 6x^2\) - Multiply the outer terms: \(\quad 2x \cdot 2 = 4x\) - Multiply the inner terms: \(\quad (-3) \cdot 3x = -9x\) - Multiply the last terms: \(\quad (-3) \cdot 2 = -6\) - Combine like terms: \[ 6x^2 + 4x - 9x - 6 = 6x^2 - 5x - 6 \] --- **2. Expanding \((2x-3)(2x+1)\):** - Multiply the first terms: \(\quad 2x \cdot 2x = 4x^2\) - Multiply the outer terms: \(\quad 2x \cdot 1 = 2x\) - Multiply the inner terms: \(\quad (-3) \cdot 2x = -6x\) - Multiply the last terms: \(\quad (-3) \cdot 1 = -3\) - Combine like terms: \[ 4x^2 + 2x - 6x - 3 = 4x^2 - 4x - 3 \] --- **3. Expanding \((3x-2)(2x+3)\):** - Multiply the first terms: \(\quad 3x \cdot 2x = 6x^2\) - Multiply the outer terms: \(\quad 3x \cdot 3 = 9x\) - Multiply the inner terms: \(\quad (-2) \cdot 2x = -4x\) - Multiply the last terms: \(\quad (-2) \cdot 3 = -6\) - Combine like terms: \[ 6x^2 + 9x - 4x - 6 = 6x^2 + 5x - 6 \] --- **4. Expanding \((3x-2)(2x-3)\):** - Multiply the first terms: \(\quad 3x \cdot 2x = 6x^2\) - Multiply the outer terms: \(\quad 3x \cdot (-3) = -9x\) - Multiply the inner terms: \(\quad (-2) \cdot 2x = -4x\) - Multiply the last terms: \(\quad (-2) \cdot (-3) = 6\) - Combine like terms: \[ 6x^2 - 9x - 4x + 6 = 6x^2 - 13x + 6 \]

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Beyond the Answer

Let’s break down these expressions with some fun tidbits that will make them clearer! Expanding expressions like \( (2x - 3)(3x + 2) \) can take on a historical twist. The distributive property, which is key here, was known as the "FOIL" method in algebra—an acronym that stands for First, Outer, Inner, Last. This approach to multiplying binomials has roots in ancient civilizations like the Babylonians who were already practicing algebraic principles thousands of years ago! Now, onto a practical application: These types of polynomial expressions come in handy in fields like engineering and physics, particularly in calculating areas, designing structures, or even modeling phenomena. If you were designing a rollercoaster, for example, you might use such equations to ensure the curves and drops are safe yet thrilling!

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