29. \( \operatorname{Lim}_{x \rightarrow 1}\left(3 x^{4}+2 x^{2}-1\right)\left(x^{3}-2\right) \) 30. \( \lim _{x \rightarrow-5}\left(x^{4}-3 x\right)\left(x^{3}+4 x^{2}-1\right) \) 31. \( \operatorname{Lim}_{x \rightarrow-2}\left(3 x^{4}+x^{2}\right)\left(x^{2}+1\right) \) 32. \( \operatorname{Lim}_{x \rightarrow 4}\left(x^{2}+2 x+3\right)(x+1) \)
Solución de inteligencia artificial de Upstudy
Responder
Solución

¡Inicia sesión para desbloquear respuestas gratis!
Una plataforma de aprendizaje en la que confían millones de estudiantes y profesores reales.

Respondido por UpStudy AI y revisado por un tutor profesional
Mind Expander
To evaluate the limit as \( x \) approaches a specific value, you can simply substitute that value into the function, provided it doesn’t lead to an undefined form. For example, in the limit \( \operatorname{Lim}_{x \rightarrow 1}\left(3 x^{4}+2 x^{2}-1\right)\left(x^{3}-2\right) \), substituting \( x = 1 \) gives \((3(1)^4 + 2(1)^2 - 1)(1^3 - 2)\), leading to a straightforward calculation. When dealing with limits that involve products of functions, remember to check for any indeterminate forms like \(0/0\) and utilize techniques such as factoring or L'Hôpital's Rule if needed. For instance, in \( \lim _{x \rightarrow -5}\left(x^{4}-3 x\right)\left(x^{3}+4 x^{2}-1\right) \), carefully substituting \(x = -5\) will help identify the limiting behavior of the function without complicated algebra.
