Fill in each blank with an integer (signed number), \begin{tabular}{|l|l|}\hline (a) $$ -4-\square=-4+(-1) $$ & ( $$ \square) $$ \ (b) $$ -3-(-6)=-3+\square $$ & $$ imes $$ \ \hline\end{tabular}

Question

Fill in each blank with an integer (signed number), \begin{tabular}{|l|l|}\hline (a) $$ -4-\square=-4+(-1) $$ & ( $$ \square) $$ \ (b) $$ -3-(-6)=-3+\square $$ & $$ 	imes $$ \ \hline\end{tabular}

UpStudy AI · Accepted Answer

We begin with part (a). The equation is
$$
-4 - \square = -4 + (-1).
$$
Let the blank be represented by $$ x $$. Then
$$
-4 - x = -4 - 1.
$$
To solve for $$ x $$, we observe that both sides have $$-4$$. Adding $$4$$ to both sides gives
$$
- x = -1.
$$
Multiplying both sides by $$-1$$ we obtain
$$
x = 1.
$$

Now, for part (b) the equation is
$$
-3 - (-6) = -3 + \square.
$$
Again, let the blank be $$ x $$. The left side simplifies using the rule of subtracting a negative number:
$$
-3 - (-6) = -3 + 6 = 3.
$$
Thus,
$$
3 = -3 + x.
$$
Adding $$3$$ to both sides yields
$$
3 + 3 = x,
$$
which simplifies to
$$
x = 6.
$$

The integer that fills the blank in part (a) is $$ 1 $$ and in part (b) is $$ 6 $$.
The integer that fills the blank in part (a) is $$1$$, and in part (b) is $$6$$.

Fill in each blank with an integer (signed number), \begin{tabular}{|l|l|}\hline (a) \( -4-\square=-4+(-1) \) & ( \( \square) \) \\ (b) \( -3-(-6)=-3+\square \) & \( \times \) \\ \hline\end{tabular}

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