Convert the given number to decimal form by expanding in powers and by using the calculator shortcut. \( 53221_{\text {six }} \) Expand \( 53221_{\text {six }} \) in powers. \( 53221_{\text {six }}=(\square)+(\square)+(\square)+(\square)+(\square) \) (Use descending order. Do not simplify.) Convert \( 53221_{\text {six }} \) to decimal form. \( 53221_{\text {six }}=\square \) (Simplify your answer.)
Solución de inteligencia artificial de Upstudy
Responder
Solución
Respondido por UpStudy AI y revisado por un tutor profesional


Beyond the Answer
To expand \( 53221_{\text{six}} \) in powers, we can express each digit with its corresponding power of six, starting from the rightmost digit (which represents \( 6^0 \)) to the leftmost digit. So, we have: \( 53221_{\text{six}} = 5 \cdot 6^4 + 3 \cdot 6^3 + 2 \cdot 6^2 + 2 \cdot 6^1 + 1 \cdot 6^0. \) Now, converting \( 53221_{\text{six}} \) to decimal form involves calculating the values of each term: - \( 5 \cdot 6^4 = 5 \cdot 1296 = 6480 \) - \( 3 \cdot 6^3 = 3 \cdot 216 = 648 \) - \( 2 \cdot 6^2 = 2 \cdot 36 = 72 \) - \( 2 \cdot 6^1 = 2 \cdot 6 = 12 \) - \( 1 \cdot 6^0 = 1 \cdot 1 = 1 \) Now, summing these values gives: \( 53221_{\text{six}} = 6480 + 648 + 72 + 12 + 1 = 7201. \) So, \( 53221_{\text{six}} = 7201. \)
