Perform the indicated operation. \( \frac{8^{2}-9^{2}}{17(-4+3)} \) \( \frac{8^{2}-9^{2}}{17(-4+3)}=\square \) (Type an integer or a simplified fraction.)

Let's break it down step by step. First, calculate \(8^{2}\) and \(9^{2}\): - \(8^{2} = 64\) - \(9^{2} = 81\) So, \(8^{2} - 9^{2} = 64 - 81 = -17\). Next, calculate the denominator \(17(-4 + 3)\): - First, find \(-4 + 3 = -1\). - So, \(17(-1) = -17\). Now, we can substitute back into the operation: \[ \frac{8^{2}-9^{2}}{17(-4+3)} = \frac{-17}{-17} = 1. \] Thus, the final result is \( \boxed{1} \).