Solve graphically \( \begin{array}{l}x+4 y=15 \\ x+2 y=7\end{array} \)
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Bonus Knowledge
To solve the system of equations graphically, start by rearranging each equation into slope-intercept form (y = mx + b). For the first equation \( x + 4y = 15 \), isolate y: \[ 4y = 15 - x \implies y = -\frac{1}{4}x + \frac{15}{4} \] For the second equation \( x + 2y = 7 \): \[ 2y = 7 - x \implies y = -\frac{1}{2}x + \frac{7}{2} \] Next, plot both lines on a graph using the y-intercepts and slopes: - The first line crosses the y-axis at \( \frac{15}{4} \) and has a slope of \( -\frac{1}{4} \). - The second line crosses the y-axis at \( \frac{7}{2} \) and has a slope of \( -\frac{1}{2} \). By finding the intersection point of the two lines, you’ll obtain the solution to the system. The intersection coordinates are the values of \( x \) and \( y \) that satisfy both equations simultaneously. This intersection can be calculated algebraically and validated through graphical representation. Try plotting the lines to find the point where they intersect visually!
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