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To simplify the expression \( (x-3)^{2} - (x+4)^{2} \), we can use the difference of squares factorization. The difference of squares is defined as \( a^2 - b^2 = (a - b)(a + b) \). Here, let \( a = (x-3) \) and \( b = (x+4) \). Then, our expression becomes: \[ ((x-3) - (x+4))((x-3) + (x+4)) \] Now, simplify each part: 1. \( (x-3) - (x+4) = x - 3 - x - 4 = -7 \) 2. \( (x-3) + (x+4) = x - 3 + x + 4 = 2x + 1 \) Putting it all together, we have: \[ -7(2x + 1) \] Distributing the -7: \[ -14x - 7 \] So, the simplified expression is: \[ -14x - 7 \]
