Solve the compound inequality. Write the solution set in interval notation. Express numbers as integers or simplified fractions. \[ 5 a-1 \geq 29 \text { or } a<-4 \] In interval notation, the solution set is \( \square \) .

Solve the equation \( 5a-1 \geq 29 \). Solve the inequality by following steps: - step0: Solve for \(a\): \(5a-1\geq 29\) - step1: Move the constant to the right side: \(5a\geq 29+1\) - step2: Add the numbers: \(5a\geq 30\) - step3: Divide both sides: \(\frac{5a}{5}\geq \frac{30}{5}\) - step4: Divide the numbers: \(a\geq 6\) Solve the equation \( a<-4 \). Solve the inequality by following steps: - step0: Solve for \(a\): \(a<-4\) The compound inequality is \(5a-1 \geq 29\) or \(a<-4\). Solving the first inequality, we have \(a \geq 6\). Solving the second inequality, we have \(a < -4\). Therefore, the solution set in interval notation is \([6, \infty) \cup (-\infty, -4)\).