Confidence in banks: A news poll conducted in 2012 asked a random sample of 1220 adults in the United States how much confidence they had in banks and other financial institutions. A total of 156 adults said that they had a great deal of confidence. An economist claims that greater than \( 12 \% \) of U.S. adults have a great deal of confidence In banks. Can you conclude that the economist's claim is true? Use both \( \alpha=0.10 \) and \( \alpha=0.01 \) levels of significance and the critical value method with the table. Part: \( 0 / 5 \) Part 1 of 5 State the appropriate null and alternate hypotheses. \( H_{0}: p=0.12 \) \( H_{1}: p>0.12 \) This hypothesis test is a right-tailed. Part: \( 1 / 5 \) test. Part 2 of 5 Find the critical values. Round the answer to three decimal places. For \( \alpha=0.10 \), the critical value is \( \square \) For \( \alpha=0.01 \), the critical value is
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To find the critical values for the hypothesis test you indicated, we need to refer to the standard normal distribution (Z-table). For \( \alpha=0.10 \), the critical value is approximately \( 1.282 \). This means that if your calculated test statistic is greater than \( 1.282 \), you would reject the null hypothesis. For \( \alpha=0.01 \), the critical value is approximately \( 2.326 \). Here again, if your calculated test statistic exceeds \( 2.326 \), you will confidently reject the null hypothesis in favor of the alternative, suggesting that more than \( 12\% \) of U.S. adults indeed have a great deal of confidence in banks.
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