\( (x, y) \rightarrow(x-9, y-5) \) Progress: \( 1 / 2 \), Write the coordinates of \( A^{\prime}, B^{\prime} \), and \( C^{\prime} \) : Part 2 of 2 (b) \( A^{\prime}(\square, \square) \) \( B^{\prime}(\square, \square) \) \( C^{\prime}(\square, \square) \)

To determine the coordinates of the translated points \( A^{\prime} \), \( B^{\prime} \), and \( C^{\prime} \) using the given translation rule \( (x, y) \rightarrow (x - 9, y - 5) \), follow these steps: ### Translation Rule: \[ (x, y) \rightarrow (x - 9, y - 5) \] This means that for any point \((x, y)\), the translated point \((x', y')\) is obtained by subtracting 9 from the original \(x\)-coordinate and 5 from the original \(y\)-coordinate. ### Applying the Translation: Assume you have the original coordinates of points \( A \), \( B \), and \( C \) as follows: - \( A(x_A, y_A) \) - \( B(x_B, y_B) \) - \( C(x_C, y_C) \) Applying the translation rule to each point: 1. **Point \( A^{\prime} \):** \[ A^{\prime}(x_A - 9, y_A - 5) \] 2. **Point \( B^{\prime} \):** \[ B^{\prime}(x_B - 9, y_B - 5) \] 3. **Point \( C^{\prime} \):** \[ C^{\prime}(x_C - 9, y_C - 5) \] ### Final Coordinates: Without the specific original coordinates of \( A \), \( B \), and \( C \), we can express the translated coordinates in terms of their original positions: - \( A^{\prime}(\mathbf{x_A - 9}, \mathbf{y_A - 5}) \) - \( B^{\prime}(\mathbf{x_B - 9}, \mathbf{y_B - 5}) \) - \( C^{\prime}(\mathbf{x_C - 9}, \mathbf{y_C - 5}) \) **Example:** If the original points are: - \( A(10, 15) \) - \( B(20, 25) \) - \( C(30, 35) \) After applying the translation: - \( A^{\prime}(10 - 9, 15 - 5) = A^{\prime}(1, 10) \) - \( B^{\prime}(20 - 9, 25 - 5) = B^{\prime}(11, 20) \) - \( C^{\prime}(30 - 9, 35 - 5) = C^{\prime}(21, 30) \) **Please provide the original coordinates of points \( A \), \( B \), and \( C \) if you need specific translated coordinates.**