(2) \( 3^{-2} \cdot 3^{4}+\sqrt[4]{16}-\frac{3}{5} \cdot \frac{25}{9}= \)

Let's break it down step by step! First, calculate \( 3^{-2} \cdot 3^{4} \): Using the laws of exponents, \( 3^{-2} \cdot 3^{4} = 3^{-2 + 4} = 3^{2} = 9 \). Next, find \( \sqrt[4]{16} \): Since \( 16 = 2^4 \), we have \( \sqrt[4]{16} = 2 \). Now, calculate \( \frac{3}{5} \cdot \frac{25}{9} \): This gives \( \frac{3 \cdot 25}{5 \cdot 9} = \frac{75}{45} = \frac{5}{3} \). Putting it all together: \[ 9 + 2 - \frac{5}{3} = 11 - \frac{5}{3} \] To subtract, convert 11 to fractions: \[ 11 = \frac{33}{3} \rightarrow \frac{33}{3} - \frac{5}{3} = \frac{28}{3} \] So the final answer is \( \frac{28}{3} \) or approximately \( 9.33 \).