In \( \triangle H \mathrm{HJ}, \mathrm{m} \angle H=(6 x-7)^{\circ}, \mathrm{m} \angle I=(x+10)^{\circ} \), and \( \mathrm{m} \angle J=(3 x-13)^{\circ} \). Find \( \mathrm{m} \angle H \).
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To find the measures of the angles in triangle \( H \mathrm{HJ} \), we can use the fact that the sum of the angles in any triangle is \( 180^\circ \). Therefore, we have: \[ \mathrm{m} \angle H + \mathrm{m} \angle I + \mathrm{m} \angle J = 180^\circ \] Substituting the given expressions for the angles: \[ (6x - 7) + (x + 10) + (3x - 13) = 180 \] Combining like terms: \[ 6x + x + 3x - 7 + 10 - 13 = 180 \] \[ 10x - 10 = 180 \] Now, adding 10 to both sides: \[ 10x = 190 \] Dividing by 10: \[ x = 19 \] Now, we can find \( \mathrm{m} \angle H \): \[ \mathrm{m} \angle H = 6x - 7 = 6(19) - 7 = 114 - 7 = 107^\circ \] Thus, \( \mathrm{m} \angle H = 107^\circ \).
