Question Re-write the quadratic function below in Standard Form \( y=6(x-4)^{2}-6 \)

Simplify the expression by following steps: - step0: Subtract the terms: \(6\left(x-4\right)^{2}-6\) - step1: Expand the expression: \(6x^{2}-48x+96-6\) - step2: Subtract the numbers: \(6x^{2}-48x+90\) To rewrite the quadratic function \( y = 6(x-4)^{2} - 6 \) in standard form, we first expand the expression. 1. Start with the given function: \[ y = 6(x-4)^{2} - 6 \] 2. Expand \( (x-4)^{2} \): \[ (x-4)^{2} = x^{2} - 8x + 16 \] 3. Substitute this back into the equation: \[ y = 6(x^{2} - 8x + 16) - 6 \] 4. Distribute the 6: \[ y = 6x^{2} - 48x + 96 - 6 \] 5. Combine like terms: \[ y = 6x^{2} - 48x + 90 \] Thus, the quadratic function in standard form is: \[ y = 6x^{2} - 48x + 90 \]