QUESTION? 2.1 Givent 4-2r<16 where \( r \in R \) 2.1.1 Solve the inequality. 2.1.2 Hence, represent your annwer is QUESTION 21.1 un a mumber line. 22 Solve simultaneously for \( x \) and \( y \) : \[ -2 x-y=10 \text { and } 3 x-4 y=-4 \]

**Solution for 2.1** 1. Start with the inequality: \[ 4 - 2r < 16 \] 2. Subtract \(4\) from both sides: \[ -2r < 12 \] 3. Divide both sides by \(-2\). Remember to reverse the inequality sign when dividing by a negative number: \[ r > -6 \] 4. The solution is: \[ r \in (-6, \infty) \] 5. On a number line, use an open circle at \(-6\) and shade all values to the right of \(-6\). --- **Solution for 22** 1. Given the system of equations: \[ -2x - y = 10 \quad \text{(1)} \] \[ 3x - 4y = -4 \quad \text{(2)} \] 2. Solve equation (1) for \(y\): \[ -y = 10 + 2x \quad \Longrightarrow \quad y = -10 - 2x \] 3. Substitute \(y = -10 - 2x\) into equation (2): \[ 3x - 4(-10 - 2x) = -4 \] 4. Simplify the equation: \[ 3x + 40 + 8x = -4 \] \[ 11x + 40 = -4 \] 5. Subtract \(40\) from both sides: \[ 11x = -44 \] 6. Divide both sides by \(11\): \[ x = -4 \] 7. Substitute \(x = -4\) back into \(y = -10 - 2x\): \[ y = -10 - 2(-4) = -10 + 8 = -2 \] 8. The solution is: \[ x = -4,\quad y = -2 \]