9. For the straight line \( 3 y=-2 x-9 \), the \( y \)-intercept is \( \begin{array}{llll}\text { (a) }(0,-9) & \text { (b) }(0,-3) & \text { (c) }(-3,0) & \text { (d) None of these }\end{array} \)

To find the \( y \)-intercept of the line represented by the equation \( 3y = -2x - 9 \), we need to set \( x = 0 \) and solve for \( y \). Substituting \( x = 0 \) gives us: \[ 3y = -2(0) - 9 \] \[ 3y = -9 \] \[ y = -3 \] Thus, the \( y \)-intercept is \( (0, -3) \). So the correct answer is \( \text{(b) }(0, -3) \).