Directions: Solve each equation for the variable. SHOW YOUR WORK FOR CREDIT! \( \begin{array}{lll}\text { 1. } 2 x+3=11 & \text { 2. } 2 x-2=0 & \text { 3. } 29=6 x-8\end{array} \)

Sure! Let’s solve each equation step by step. 1. For the equation \(2x + 3 = 11\): - First, subtract 3 from both sides: \(2x + 3 - 3 = 11 - 3\) - This simplifies to \(2x = 8\). - Next, divide both sides by 2: \(x = \frac{8}{2}\). - Therefore, \(x = 4\). 2. For the equation \(2x - 2 = 0\): - First, add 2 to both sides: \(2x - 2 + 2 = 0 + 2\). - This simplifies to \(2x = 2\). - Next, divide both sides by 2: \(x = \frac{2}{2}\). - Therefore, \(x = 1\). 3. For the equation \(29 = 6x - 8\): - First, add 8 to both sides: \(29 + 8 = 6x - 8 + 8\). - This simplifies to \(37 = 6x\). - Next, divide both sides by 6: \(x = \frac{37}{6}\). - Therefore, \(x \approx 6.17\) (or leave it as the fraction \(\frac{37}{6}\)). And that's it! We've solved all three equations.