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Determine whether \( (5,-2) \) is a solution of \( 6 q-7 p=48 \). Unless stated otherwise, to determine whether an ordered pair is a solution of an equation, use the first number in the ordered pair to replace the variable that occurs first alphabetically. Use the second number in the ordered pair to replace the other variable. The variable \( p \) occurs first alphabetically amongst the variables in the given equation. So substitute \( \square \) for \( p \) and \( \square \) for \( q \) in the equation \( 6 q-7 p=48 \).

Ask by Perkins Guerrero. in the United States
Mar 14,2025

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\( (5, -2) \) is not a solution of the equation \( 6q - 7p = 48 \).

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To determine whether \( (5,-2) \) is a solution to the equation \( 6q - 7p = 48 \), we follow the instructions provided. Here, we substitute \( p \) with \( 5 \) (the first number) and \( q \) with \( -2 \) (the second number). Now, substitute \( p = 5 \) and \( q = -2 \) into the equation: \[ 6(-2) - 7(5) = 48 \] Calculating the left side gives: \[ -12 - 35 = -47 \] Since \(-47\) does not equal \(48\), the ordered pair \( (5, -2) \) is not a solution to the equation \( 6q - 7p = 48 \).

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