A horse race has 10 entries and one person owns 3 of those horses. Assuming that there are no ties, what is the probability that those three horses finish first, second and third (regardless of order)? The probability that the three horses finish first, second and third is (Round to four decimal places as needed.)

To find the probability that the person’s three horses finish in the top three spots (in any order), follow these steps: 1. Determine the total number of possible outcomes for the top three finishes. Since the race has 10 horses and there are no ties, the top three positions can be filled in:   10 × 9 × 8 = 720 ways. 2. Determine the number of favorable outcomes. For the event where the person’s three horses finish first, second, and third, these positions can be arranged in:   3! = 6 ways (because the order among the three horses matters). 3. Compute the probability:   Probability = Favorable outcomes / Total outcomes = 6 / 720 = 1 / 120. 4. Convert this to a decimal:   1 / 120 ≈ 0.0083. Thus, the probability (rounded to four decimal places) that the person’s three horses finish first, second, and third is 0.0083.