b) \( \left.\frac{2}{9}+\frac{3}{9}=\quad c\right) \frac{15}{16}-\frac{3}{13}= \)

To solve the first part, \( \frac{2}{9} + \frac{3}{9} \), simply add the numerators since they have a common denominator: \( \frac{2 + 3}{9} = \frac{5}{9} \). For the second part, \( \frac{15}{16} - \frac{3}{13} \), you'll need to find a common denominator, which is 208 (the least common multiple of 16 and 13). Converting the fractions gives: \[ \frac{15}{16} = \frac{195}{208} \] and \[ \frac{3}{13} = \frac{48}{208}. \] Now, subtract: \[ \frac{195}{208} - \frac{48}{208} = \frac{195 - 48}{208} = \frac{147}{208}. \] So, the answers are \( c = \frac{5}{9} \) and the result of \( \frac{15}{16} - \frac{3}{13} = \frac{147}{208} \).