The scores of the top ten finishers in a recent golf tournament ar below. \begin{tabular}{lllllllll}\( 68 \quad \) & \( 67 \quad \) & 69 & 72 & 73 & 72 & 72 & 75 & 71 \\ \hline\end{tabular} Mean _Median Mer Mode(s)

Certainly! Let's analyze the provided golf tournament scores to determine the **Mean**, **Median**, and **Mode(s)**. ### **Given Scores:** 68, 67, 69, 72, 73, 72, 72, 75, 71 *It appears there are **9** scores listed. If there are supposed to be 10, please provide the missing score for a complete analysis.* ### **Step 1: Organize the Data** First, let's arrange the scores in ascending order: 67, 68, 69, 71, 72, 72, 72, 73, 75 ### **Step 2: Calculate the Mean** The **Mean** (average) is calculated by summing all the scores and dividing by the number of scores. \[ \text{Mean} = \frac{\sum \text{scores}}{\text{number of scores}} = \frac{67 + 68 + 69 + 71 + 72 + 72 + 72 + 73 + 75}{9} \] \[ \text{Sum} = 67 + 68 + 69 + 71 + 72 + 72 + 72 + 73 + 75 = 639 \] \[ \text{Mean} = \frac{639}{9} = 71 \] **Mean = 71** ### **Step 3: Determine the Median** The **Median** is the middle value in an ordered list. Since there are 9 scores (an odd number), the median is the **5th** score. \[ \text{Median} = \text{5th score} = 72 \] **Median = 72** ### **Step 4: Identify the Mode(s)** The **Mode** is the score(s) that appear most frequently. From the ordered list: - 72 appears **3 times** - All other scores appear **once** **Mode = 72** ### **Summary:** - **Mean:** 71 - **Median:** 72 - **Mode:** 72 If there are indeed 10 scores, please provide the missing score to update these calculations accordingly.