Graph the equation \( 5 y-4 x=-20 \) and identify the y-intercept. To graph a linear equation, two points are essential to determine a straight line. In this case, use the two points determined by the first and third rows of the table above. The remaining point, (5,0), can be used as a check. Use the graphing tool to graph the line using two points.

1. Begin with the given equation: \[ 5y - 4x = -20 \] 2. Solve for \(y\) to put the equation in slope-intercept form. Add \(4x\) to both sides: \[ 5y = 4x - 20 \] Then divide both sides by 5: \[ y = \frac{4}{5}x - 4 \] 3. The equation is now in the form \(y = mx + b\), where the y-intercept is the point: \[ (0, -4) \] 4. Pick two points from the table for graphing. Using the first row, when \(x = 0\): \[ y = \frac{4}{5}(0) - 4 = -4 \] This gives the point \((0, -4)\). 5. Using the third row of the table, choose a value that is not \((5,0)\) (which is reserved as a check). For example, let \(x = -5\): \[ y = \frac{4}{5}(-5) - 4 = -4 - 4 = -8 \] This gives the point \((-5, -8)\). 6. Plot the two points \((0, -4)\) and \((-5, -8)\) on the coordinate plane, then draw the straight line through these points. 7. As a check, verify that the point \((5,0)\) lies on the line. Substitute \(x = 5\) into the equation: \[ y = \frac{4}{5}(5) - 4 = 4 - 4 = 0 \] Since the calculation gives \(y = 0\), the point \((5, 0)\) is indeed on the line. The y-intercept of the graph is \((0, -4)\).