Pregunta
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Given the differential equation
.
List the constant (i.e. equilibrium) solutions to
this differential equation in increasing order and
indicate whether or not these solutions are
stable, semi-stable, or unstable. Confirm your
answer by plotting the slope field.
stable

Ask by Marsh Fernandez. in the United States
Mar 27,2025

Solución de inteligencia artificial de Upstudy

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The equilibrium solutions are:
  1. (unstable)
  2. (unstable)
  3. (unstable)
  4. (stable)
Slope Field Confirmation: The slope field shows that solutions near tend to move towards it, confirming its stability, while solutions near the other equilibrium points move away, confirming their instability.

Solución

Alright, I need to analyze the given differential equation to find its constant (equilibrium) solutions, list them in increasing order, and determine their stability. Additionally, I need to confirm the stability by plotting the slope field.
First, let’s identify the equilibrium solutions. These are the values of where . So, I’ll set the right-hand side of the equation to zero:
This equation will be zero when any of the factors is zero. Therefore, the equilibrium solutions are:
  1. (with multiplicity 3)
  2. (with multiplicity 2)
Now, I’ll list these solutions in increasing order:
Next, I need to determine the stability of each equilibrium solution. To do this, I’ll analyze the sign of around each equilibrium point.
  1. For :
    • To the left of , all factors , , , and are negative except , which is positive.
    • To the right of , becomes positive, while the other factors remain the same.
    • The sign of changes from negative to positive as increases through , indicating that is unstable.
  2. For :
    • Since has a multiplicity of 3, the behavior around is more complex.
    • To the left of , is negative, and to the right, it becomes positive.
    • The other factors , , and are positive on both sides.
    • The sign of changes from negative to positive as increases through , suggesting that is unstable.
  3. For :
    • is always positive.
    • is positive to the right of and negative to the left.
    • is positive to the right of and negative to the left.
    • is negative to the left of and positive to the right.
    • The sign of changes from negative to positive as increases through , indicating that is unstable.
  4. For :
    • is positive to the right of and negative to the left.
    • The other factors , , and are positive on both sides.
    • The sign of changes from positive to negative as increases through , suggesting that is stable.
To confirm these findings, I’ll plot the slope field of the differential equation. The slope field will show the direction of the solutions at various points, which should align with the stability analysis:
  • Around , , and , the slopes change from negative to positive, indicating instability.
  • Around , the slopes change from positive to negative, indicating stability.
This graphical confirmation supports the analytical determination of the stability of each equilibrium solution.

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Mind Expander

To find the constant (equilibrium) solutions to the differential equation , we set . The equation equals zero when any factors are zero, giving us the equilibrium solutions:
Next, we determine the stability of each equilibrium point by examining the sign of around these points:
  • : The sign of changes from positive to negative, indicating it is a stable equilibrium.
  • : The sign of changes from negative to positive, indicating it is an unstable equilibrium.
  • : The sign of changes from negative to positive, indicating it is an unstable equilibrium.
  • : The sign of changes from positive to negative, indicating it is a stable equilibrium.
So, the equilibrium solutions in increasing order with their stability are:
  • (stable)
  • (unstable)
  • (unstable)
  • (stable)
To confirm your answer by plotting the slope field, use a software tool like Desmos or Python’s Matplotlib library to visualize it. The slope field will illustrate the behavior of solutions around the equilibrium points, confirming their respective stabilities.

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