\( \triangle A B C \cong \triangle D E F \). Find the measure of the given angles. \( m \angle A=x+25 \) \( m \angle D=2 x \) \( \begin{array}{l}m \angle A=\square^{\circ} \\ \text { (Do not include the degree symbol in your answer.) } \\ m \angle D=\square^{\circ} \\ \text { (Do not include the degree symbol in your answer.) }\end{array} \)

Since the triangles \( \triangle ABC \) and \( \triangle DEF \) are congruent, their corresponding angles are equal. Therefore, we can set up the equation: \[ x + 25 = 2x \] To solve for \( x \), we subtract \( x \) from both sides: \[ 25 = 2x - x \] \[ 25 = x \] Now we can find the measures of the angles: For \( m \angle A \): \[ m \angle A = x + 25 = 25 + 25 = 50 \] For \( m \angle D \): \[ m \angle D = 2x = 2 \times 25 = 50 \] Thus, the measures of the angles are: \( m \angle A = 50 \) \( m \angle D = 50 \) The final answers are: \[ \begin{array}{l} m \angle A = 50 \\ m \angle D = 50 \end{array} \]