Find the $$ x $$-intercept and $$ y $$-intercept of the line. $$ \begin{array}{l}5 x+2 y=-8 \ x \text {-intercept: } \square\end{array} $$

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1. **Find the $$x$$-intercept:**  
   The $$x$$-intercept occurs when $$ y = 0 $$. Substitute $$ y = 0 $$ into the equation:
   $$
   5x + 2(0) = -8 \quad \Rightarrow \quad 5x = -8
   $$
   Solve for $$x$$:
   $$
   x = -\frac{8}{5}
   $$
   Thus, the $$x$$-intercept is $$\left(-\frac{8}{5}, 0\right)$$.

2. **Find the $$y$$-intercept:**  
   The $$y$$-intercept occurs when $$ x = 0 $$. Substitute $$ x = 0 $$ into the equation:
   $$
   5(0) + 2y = -8 \quad \Rightarrow \quad 2y = -8
   $$
   Solve for $$y$$:
   $$
   y = -4
   $$
   Thus, the $$y$$-intercept is $$\left(0, -4\right)$$.

3. **Summary:**  
   - $$x$$-intercept: $$\left(-\frac{8}{5}, 0\right)$$  
   - $$y$$-intercept: $$\left(0, -4\right)$$
The $$x$$-intercept is $$\left(-\frac{8}{5}, 0\right)$$ and the $$y$$-intercept is $$\left(0, -4\right)$$.

Find the \( x \)-intercept and \( y \)-intercept of the line. \[ \begin{array}{l}5 x+2 y=-8 \\ x \text {-intercept: } \square\end{array} \]

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