Solve $$ 3+(3+3) \div 5 imes 3-4^{2} $$

Question

Solve $$ 3+(3+3) \div 5 	imes 3-4^{2} $$

UpStudy AI · Accepted Answer

1. **Evaluate the parentheses:**  
   $$
   3+3=6
   $$  
   The expression becomes:  
   $$
   3+\frac{6}{5}\times 3-4^2
   $$

2. **Evaluate the exponent:**  
   $$
   4^2=16
   $$  
   Now the expression is:  
   $$
   3+\frac{6}{5}\times 3-16
   $$

3. **Perform the multiplication and division (from left to right):**  
   First, compute the division:  
   $$
   \frac{6}{5}
   $$  
   Then, multiply by 3:  
   $$
   \frac{6}{5}\times 3=\frac{18}{5}
   $$  
   So the expression now is:  
   $$
   3+\frac{18}{5}-16
   $$

4. **Combine like terms by expressing all numbers with a common denominator:**  
   $$
   3=\frac{15}{5} \quad \text{and} \quad 16=\frac{80}{5}
   $$  
   The expression becomes:  
   $$
   \frac{15}{5}+\frac{18}{5}-\frac{80}{5}
   $$

5. **Add and subtract the fractions:**  
   $$
   \frac{15+18-80}{5}=\frac{-47}{5}
   $$

The final answer is:  
$$
-\frac{47}{5}
$$
The final answer is $$ -\frac{47}{5} $$.

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