\( ( x ^ { 2 } - 3 x + 5 ) - ( - 4 x ^ { 2 } + 8 x + 9 ) = \square + \square = \square + \square = \square = \square \)

To solve the expression \( ( x ^ { 2 } - 3 x + 5 ) - ( - 4 x ^ { 2 } + 8 x + 9 ) \), we will follow these steps: 1. Distribute the negative sign across the second polynomial. 2. Combine like terms. Let's start with the first step: 1. Distributing the negative sign: \[ ( x ^ { 2 } - 3 x + 5 ) - ( - 4 x ^ { 2 } + 8 x + 9 ) = x ^ { 2 } - 3 x + 5 + 4 x ^ { 2} - 8 x - 9 \] 2. Now, we will combine like terms: - Combine \( x^2 \) terms: \( x^2 + 4x^2 = 5x^2 \) - Combine \( x \) terms: \( -3x - 8x = -11x \) - Combine constant terms: \( 5 - 9 = -4 \) Putting it all together, we have: \[ 5x^2 - 11x - 4 \] Now, we can express this in the format requested: \[ 5x^2 + (-11x) + (-4) = \square + \square + \square \] Thus, the final answer is: \[ 5x^2 + (-11x) + (-4) = 5 + (-11) + (-4) = \square + \square + \square \] So, the values for the squares are: - First square: \( 5 \) - Second square: \( -11 \) - Third square: \( -4 \)