\begin{tabular}{l} Multiply the following: \\ \( \qquad-2 x^{2}\left(3 x^{2}+4 x-5\right) \) \\ Select the correct answer below: \\ \( -6 x^{4}-8 x^{3}+10 x^{2} \) \\ \( -6 x^{4}-8 x^{3}-10 x^{2} \) \\ \( -6 x^{4}+8 x^{3}-10 x^{2} \) \\ \( -6 x^{4}-8 x^{2}+10 \) \\ \( -6 x^{4}+8 x^{2}+10 \) \\ \hline\end{tabular}

When you multiply the expression \(-2x^{2}(3x^{2}+4x-5)\), you'll want to distribute \(-2x^{2}\) to each term inside the parentheses. When you do that, you’ll slice through each term like a hot knife through butter! First, \(-2x^{2} \times 3x^{2} = -6x^{4}\). Next, \(-2x^{2} \times 4x = -8x^{3}\). Finally, \(-2x^{2} \times -5 = +10x^{2}\). So altogether, we’ve got \(-6x^{4} - 8x^{3} + 10x^{2}\). So, the correct answer here is: \(-6x^{4}-8x^{3}+10x^{2}\). This fun little distribution showcases how algebra can dance and shimmy to create new expressions! And remember, always keep an eye on those negative signs—they can be tricky little rascals!