2b.) The students in Naomi's class earned \( 20 \% \) of the selling price of each calendar sold this year and last year. . At last year's selling price, Naomi's class sold 650 calendars. Fill in the blanks to correctly complete the statement. The students in Naomi's class earned more money by \( \$ 28 \). 800 calendars.

Let's denote the selling price of each calendar as \( x \) dollars. Given that the students in Naomi's class earned \( 20\% \) of the selling price of each calendar sold this year and last year, we can express the amount earned by the students in Naomi's class as \( 0.20x \) dollars per calendar. Last year, Naomi's class sold 650 calendars, so the total amount earned by the students in Naomi's class last year is \( 0.20x \times 650 \) dollars. This year, Naomi's class sold 800 calendars, so the total amount earned by the students in Naomi's class this year is \( 0.20x \times 800 \) dollars. The statement mentions that the students in Naomi's class earned more money by $28.800 calendars. This means that the difference in the total amount earned by the students in Naomi's class between this year and last year is $28.800. We can set up the equation based on the information provided: \[ 0.20x \times 800 - 0.20x \times 650 = 28.800 \] Now, we can solve this equation to find the value of \( x \), which represents the selling price of each calendar. Solve the equation by following steps: - step0: Solve for \(x\): \(0.2x\times 800-0.2x\times 650=28.8\) - step1: Simplify: \(30x=28.8\) - step2: Divide both sides: \(\frac{30x}{30}=\frac{28.8}{30}\) - step3: Divide the numbers: \(x=\frac{24}{25}\) The selling price of each calendar is $0.96. Now, we can calculate the total amount earned by the students in Naomi's class last year and this year: Last year: \( 0.20 \times 0.96 \times 650 = \$ 129.60 \) This year: \( 0.20 \times 0.96 \times 800 = \$ 153.60 \) The difference in the total amount earned by the students in Naomi's class between this year and last year is indeed $28.800, as stated in the problem.