OR NNITON2 (ג) What is the molarity of s whltion mads using 45.0 g of NaCl and enough water to give t hiee of whube? (iid) What is the volume ef a $$ 0: 2 \mathrm{M} $$ AgNO, soluticen sontaining 85 grams of AgNO? (ikin 1hokgale Zore thited ins mh of a 1.6 M splution of Licl to 1.0 L . detemine the new evesentratisa all ibe whition of LCK1

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Let's break down the problem step by step and solve each part.

### Part (g): Molarity of NaCl Solution

1. **Known Conditions:**
   - Mass of NaCl = 45.0 g
   - Molar mass of NaCl = 58.44 g/mol (calculated as Na: 22.99 g/mol + Cl: 35.45 g/mol)
   - Volume of solution = 3 L

2. **Calculate the number of moles of NaCl:**
   $$
   \text{Moles of NaCl} = \frac{\text{mass}}{\text{molar mass}} = \frac{45.0 \, \text{g}}{58.44 \, \text{g/mol}}
   $$

3. **Calculate the molarity (M):**
   $$
   \text{Molarity} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} = \frac{\text{moles of NaCl}}{3 \, \text{L}}
   $$

### Part (iid): Volume of 0.2 M AgNO₃ Solution

1. **Known Conditions:**
   - Mass of AgNO₃ = 85 g
   - Molar mass of AgNO₃ = 169.87 g/mol (calculated as Ag: 107.87 g/mol + N: 14.01 g/mol + O: 3 × 16.00 g/mol)
   - Concentration = 0.2 M

2. **Calculate the number of moles of AgNO₃:**
   $$
   \text{Moles of AgNO₃} = \frac{85 \, \text{g}}{169.87 \, \text{g/mol}}
   $$

3. **Calculate the volume of the solution:**
   $$
   \text{Volume} = \frac{\text{moles of AgNO₃}}{0.2 \, \text{M}}
   $$

### Part (ikin): New Concentration of LiCl Solution

1. **Known Conditions:**
   - Initial concentration of LiCl = 1.6 M
   - Initial volume = 1.0 L
   - Final volume after dilution = 1.0 L (assuming no additional water is added)

2. **Calculate the number of moles of LiCl:**
   $$
   \text{Moles of LiCl} = \text{concentration} \times \text{volume} = 1.6 \, \text{M} \times 1.0 \, \text{L}
   $$

3. **Calculate the new concentration after dilution:**
   $$
   \text{New Concentration} = \frac{\text{moles of LiCl}}{\text{final volume}}
   $$

Now, let's perform the calculations for each part.
Calculate the value by following steps:
- step0: Calculate:
  $$1.6\times 1$$
- step1: Multiply:
  $$1.6$$
Calculate or simplify the expression $$ 85/169.87 $$.
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{85}{169.87}$$
- step1: Convert the expressions:
  $$\frac{85}{\frac{16987}{100}}$$
- step2: Multiply by the reciprocal:
  $$85\times \frac{100}{16987}$$
- step3: Multiply:
  $$\frac{85\times 100}{16987}$$
- step4: Multiply:
  $$\frac{8500}{16987}$$
Calculate or simplify the expression $$ 45.0/58.44 $$.
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{45}{58.44}$$
- step1: Convert the expressions:
  $$\frac{45}{\frac{1461}{25}}$$
- step2: Multiply by the reciprocal:
  $$45\times \frac{25}{1461}$$
- step3: Reduce the numbers:
  $$15\times \frac{25}{487}$$
- step4: Multiply:
  $$\frac{15\times 25}{487}$$
- step5: Multiply:
  $$\frac{375}{487}$$
Calculate or simplify the expression $$ 1.6/1.0 $$.
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{1.6}{1}$$
- step1: Convert the expressions:
  $$\frac{\frac{8}{5}}{1}$$
- step2: Divide the terms:
  $$\frac{8}{5}$$
Calculate or simplify the expression $$ 0.500383/0.2 $$.
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{0.500383}{0.2}$$
- step1: Convert the expressions:
  $$\frac{\frac{500383}{1000000}}{\frac{1}{5}}$$
- step2: Multiply by the reciprocal:
  $$\frac{500383}{1000000}\times 5$$
- step3: Reduce the numbers:
  $$\frac{500383}{200000}\times 1$$
- step4: Multiply:
  $$\frac{500383}{200000}$$
Calculate or simplify the expression $$ 0.770021/3 $$.
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{0.770021}{3}$$
- step1: Convert the expressions:
  $$\frac{\frac{770021}{1000000}}{3}$$
- step2: Multiply by the reciprocal:
  $$\frac{770021}{1000000}\times \frac{1}{3}$$
- step3: Multiply the fractions:
  $$\frac{770021}{1000000\times 3}$$
- step4: Multiply:
  $$\frac{770021}{3000000}$$
Let's summarize the results for each part of the problem:

### Part (g): Molarity of NaCl Solution
1. **Moles of NaCl:**
   $$
   \text{Moles of NaCl} \approx 0.770021 \, \text{mol}
   $$

2. **Molarity Calculation:**
   $$
   \text{Molarity} = \frac{0.770021}{3} \approx 0.256674 \, \text{M}
   $$

### Part (iid): Volume of 0.2 M AgNO₃ Solution
1. **Moles of AgNO₃:**
   $$
   \text{Moles of AgNO₃} \approx 0.500383 \, \text{mol}
   $$

2. **Volume Calculation:**
   $$
   \text{Volume} = \frac{0.500383}{0.2} \approx 2.501915 \, \text{L}
   $$

### Part (ikin): New Concentration of LiCl Solution
1. **Moles of LiCl:**
   $$
   \text{Moles of LiCl} = 1.6 \, \text{mol}
   $$

2. **New Concentration Calculation:**
   $$
   \text{New Concentration} = \frac{1.6}{1.0} = 1.6 \, \text{M}
   $$

### Final Results:
- **Molarity of NaCl Solution:** $$ \approx 0.256674 \, \text{M} $$
- **Volume of 0.2 M AgNO₃ Solution:** $$ \approx 2.501915 \, \text{L} $$
- **New Concentration of LiCl Solution:** $$ 1.6 \, \text{M} $$

If you have any further questions or need additional calculations, feel free to ask!
- **Molarity of NaCl Solution:** Approximately 0.26 M - **Volume of 0.2 M AgNO₃ Solution:** Approximately 2.5 L - **New Concentration of LiCl Solution:** 1.6 M

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