Pregunta
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20- ft ladder is standing up against a wall. The distance between the base of the ladder and the wall is 4 ft tess than the distance between the top of the ladder nd the base of the wall. Find the distance between the base of the ladder and the wall.

Ask by Chan Stephens. in the United States
Mar 09,2025

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The distance between the base of the ladder and the wall is 12 feet.

Solución

Let's denote the distance between the base of the ladder and the wall as \( x \) feet. Given that the distance between the top of the ladder and the base of the wall is 4 feet more than the distance between the base of the ladder and the wall, we can express this as: \[ x + 4 \] The ladder forms a right-angled triangle with the wall and the ground. Using the Pythagorean theorem, we can relate the lengths of the sides of the triangle: \[ x^2 + (x + 4)^2 = 20^2 \] Now, we can solve this equation to find the value of \( x \), which represents the distance between the base of the ladder and the wall. Solve the quadratic equation by following steps: - step0: Solve by factoring: \(x^{2}+\left(x+4\right)^{2}=20^{2}\) - step1: Expand the expression: \(2x^{2}+8x+16=400\) - step2: Move the expression to the left side: \(2x^{2}+8x-384=0\) - step3: Factor the expression: \(2\left(x-12\right)\left(x+16\right)=0\) - step4: Divide the terms: \(\left(x-12\right)\left(x+16\right)=0\) - step5: Separate into possible cases: \(\begin{align}&x-12=0\\&x+16=0\end{align}\) - step6: Solve the equation: \(\begin{align}&x=12\\&x=-16\end{align}\) - step7: Rewrite: \(x_{1}=-16,x_{2}=12\) The solutions to the equation are \( x = -16 \) and \( x = 12 \). Since the distance between the base of the ladder and the wall cannot be negative, the correct solution is \( x = 12 \) feet. Therefore, the distance between the base of the ladder and the wall is 12 feet.

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Beyond the Answer

To solve this, we can use the Pythagorean theorem. Here, the ladder forms a right triangle with the wall and the ground. Let \( x \) be the distance between the base of the ladder and the wall. According to the problem, the distance from the top of the ladder to the base of the wall is \( x + 4 \). Using the Pythagorean theorem: \[ x^2 + (x + 4)^2 = 20^2 \] Expanding the equation: \[ x^2 + (x^2 + 8x + 16) = 400 \] \[ 2x^2 + 8x + 16 = 400 \] \[ 2x^2 + 8x - 384 = 0 \] Dividing the entire equation by 2 simplifies to: \[ x^2 + 4x - 192 = 0 \] Now, to find \( x \), we can use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] where \( a = 1, b = 4, c = -192 \). Calculating the discriminant: \[ b^2 - 4ac = 4^2 - 4 \cdot 1 \cdot (-192) = 16 + 768 = 784 \] So the solutions are: \[ x = \frac{-4 \pm 28}{2} \] This gives us two potential solutions: \[ x = \frac{24}{2} = 12 \quad \text{and} \quad x = \frac{-32}{2} = -16 \] Since the distance cannot be negative, the distance between the base of the ladder and the wall is \( 12 \) feet. --- Did you know that as far back as the ancient Greeks, mathematicians like Pythagoras were already studying relationships in right triangles? The Pythagorean theorem, discovered by them, has become a cornerstone in geometry, helping solve numerous practical problems involving heights and distances—even in construction design today! As fun as it is to solve these problems, remember that it's easy to mix up which side of the equation sides correspond to the ladder, wall, and ground! Always double-check which distances you are using—getting the relationship wrong can lead to incorrect conclusions, so draw a quick sketch if needed!

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