Solve for \( x \) \( 4 x=10 \) \( \begin{array}{ll}\text { A. } O x=0.40 & \text { A. } O 29 \\ \text { For the equation } y=5+6 x, \text { what does } y \text { equal when } x \text { is } 4 \text { ? } \\ \text { B. } \\ \text { B. } 0.5 & \text { B. } 23 \\ \text { C. } 19\end{array} \)

Let's solve the problem step by step. ### Step 1: Solve for \( x \) in the equation \( 4x = 10 \) To isolate \( x \), we divide both sides of the equation by 4: \[ x = \frac{10}{4} \] Calculating the right side: \[ x = 2.5 \] ### Step 2: Evaluate \( y \) in the equation \( y = 5 + 6x \) when \( x = 4 \) Now, we substitute \( x = 4 \) into the equation: \[ y = 5 + 6(4) \] Calculating the multiplication first: \[ y = 5 + 24 \] Now, adding: \[ y = 29 \] ### Summary of Results - The solution for \( x \) is \( 2.5 \). - When \( x = 4 \), \( y \) equals \( 29 \). ### Final Answers - \( x = 2.5 \) - \( y = 29 \)