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19 Mark for Review The value of an autographed baseball increased by \( 178 \% \) from the end of 2012 to the end of 2013 and then decreased by \( 21 \% \) from the end of 2013 to the end of 2014 . What was the net percentage increase in the value of the autographed baseball from the end of 2012 to the end of 2014 ? (A) \( 119.62 \% \)

Ask by Lane Floyd. in Greece
Mar 15,2025

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The net percentage increase in the value of the autographed baseball from the end of 2012 to the end of 2014 is **119.62%**.

Solución

Let the value of the baseball at the end of 2012 be \( V \). 1. From the end of 2012 to the end of 2013, the value increased by \( 178\% \). This means the new value is \[ V \times (1 + 1.78) = V \times 2.78. \] 2. From the end of 2013 to the end of 2014, the value decreased by \( 21\% \). The new value is then \[ V \times 2.78 \times (1 - 0.21) = V \times 2.78 \times 0.79. \] 3. Calculate the net multiplier: \[ 2.78 \times 0.79 = 2.1962. \] So, the value at the end of 2014 is \[ V \times 2.1962. \] 4. The net increase in value from the end of 2012 is obtained by subtracting the original value \( V \): \[ V \times 2.1962 - V = V(2.1962 - 1) = V \times 1.1962. \] 5. Converting the net increase into a percentage: \[ 1.1962 \times 100\% = 119.62\%. \] Thus, the net percentage increase in the value of the autographed baseball is \( 119.62\% \).

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Let’s break it down! Suppose the value of the baseball at the end of 2012 was \( V \). A \( 178\% \) increase means it grows to \( V + 1.78V = 2.78V \) by the end of 2013. Now, for the decrease of \( 21\% \) from the end of 2013 to the end of 2014, we take \( 2.78V \) and reduce it by \( 21\% \): New Value = \( 2.78V - 0.21 \cdot 2.78V = 2.78V \cdot (1 - 0.21) = 2.78V \cdot 0.79 \). Calculating \( 2.78 \times 0.79 = 2.1942V \). Now, to find the net percentage increase from the value at the end of 2012 to the end of 2014: \[ \text{Net Increase} = \frac{2.1942V - V}{V} \times 100\% = 119.42\% \] So the value increased by approximately \( 119.42\% \). Since \( (A) \) \( 119.62\% \) is the closest, it’s a reasonable choice! Just a little extra: always double-check calculations for tiny math slips; they can make a big difference in the end!

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