3. \( 1 \frac{1}{4}+1 \frac{1}{6}-1 \frac{1}{8}=?+1 \frac{1}{12} \) \( \begin{array}{ll}\text { (a) } \frac{5}{24} & \text { (b) } \frac{7}{24} \\ \text { (d) } \frac{7}{12} & \text { (e) None of these }\end{array} \)

To solve for \( ? \) in the equation \( 1 \frac{1}{4}+1 \frac{1}{6}-1 \frac{1}{8}=?+1 \frac{1}{12} \), we can first convert the mixed numbers into improper fractions. We have: \[ 1 \frac{1}{4} = \frac{5}{4}, \quad 1 \frac{1}{6} = \frac{7}{6}, \quad 1 \frac{1}{8} = \frac{9}{8}, \quad 1 \frac{1}{12} = \frac{13}{12}. \] Now, substituting these into the equation gives us: \[ \frac{5}{4} + \frac{7}{6} - \frac{9}{8} = ? + \frac{13}{12}. \] Finding a common denominator (which in this case is 24), we convert each fraction: \[ \frac{5}{4} = \frac{30}{24}, \quad \frac{7}{6} = \frac{28}{24}, \quad \frac{9}{8} = \frac{27}{24}, \quad \frac{13}{12} = \frac{26}{24}. \] Substituting these back into the equation yields: \[ \frac{30}{24} + \frac{28}{24} - \frac{27}{24} = ? + \frac{26}{24}. \] Calculating the left side: \[ \frac{30 + 28 - 27}{24} = \frac{31}{24}. \] So we have: \[ \frac{31}{24} = ? + \frac{26}{24}. \] To find \( ? \), we can rearrange the equation: \[ ? = \frac{31}{24} - \frac{26}{24} = \frac{5}{24}. \] Thus, the answer to the original question is \( \frac{5}{24} \) which corresponds to option (a).