According to the National Institute of Mental Health the prevalence of a current ADHD diagnosis amongst U.S. Adults aged \( 25-34 \) from 2001-2003 was \( 3.8 \% \). Calculate the mean and standard deviation for a sampling distribution using sample size 300 . (a) The mean is Do not round this answer. (b) The standard deviation is Round this answer to 4 decimal places.
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(a) The mean of the sampling distribution for the proportion is equal to the population proportion (p), which in this case is \( p = 0.038 \). Thus, the mean is: Mean = 0.038 (b) The standard deviation of the sampling distribution (standard error) can be calculated using the formula: \[ \text{Standard Deviation (SE)} = \sqrt{\frac{p(1 - p)}{n}} \] Where: - \( p = 0.038 \) - \( n = 300 \) Substituting the values: \[ SE = \sqrt{\frac{0.038(1 - 0.038)}{300}} \approx \sqrt{\frac{0.038 \cdot 0.962}{300}} \approx \sqrt{\frac{0.036596}{300}} \approx \sqrt{0.000121986} \approx 0.0110 \] Rounding this to four decimal places, we get: Standard Deviation ≈ 0.0110
