11. If the area of a parallelogram is \( 16 \mathrm{~cm}^{2} \) and the base is 8 cm , find the height. \( \begin{array}{llll}\text { a) } 1 \mathrm{~cm} & \text { b) } 2 \mathrm{~cm} & \text { c) } 3 \mathrm{~cm} & \text { d) } 4 \mathrm{~cm}\end{array} \)

To find the height of the parallelogram, you can use the formula for the area of a parallelogram, which is given by: \[ \text{Area} = \text{base} \times \text{height} \] In this case, the area is \(16 \, \text{cm}^2\) and the base is \(8 \, \text{cm}\). Plugging in the values, we get: \[ 16 = 8 \times \text{height} \] To find the height, divide both sides by \(8\): \[ \text{height} = \frac{16}{8} = 2 \, \text{cm} \] Thus, the height of the parallelogram is \(2 \, \text{cm}\). The correct answer is **b) 2 cm**. Now, here are the fun bits! In ancient Egypt, parallelograms were used in the designs of various structures like the pyramids, showcasing that even geometry holds a royal touch! These shapes were also crucial for the Egyptians in land surveying, helping them to calculate areas of farmland with incredible precision—mind-blowing given their era! When calculating the height, a common mistake is to confuse base and height dimensions. Remember that in a parallelogram, the height is always perpendicular to the base. So, if you have a tilted figure, don’t measure the slant—it will get you all mixed up! Always drop a perpendicular from the top to the base to find that height!