9:54 AM 1 19.5KB/s R6 4is Prove that : \( \cos \frac{2 \pi^{\mathrm{c}}}{7}+\cos \frac{4 \pi^{\mathrm{c}}}{7}+\cos \frac{6 \pi^{\mathrm{c}}}{7}=-\frac{1}{2} \) x) Gauth
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To prove that \( \cos \frac{2 \pi c}{7} + \cos \frac{4 \pi c}{7} + \cos \frac{6 \pi c}{7} = -\frac{1}{2} \), we can utilize the identity involving the roots of unity. The seventh roots of unity are given by \( e^{2 \pi i k / 7} \) for \( k = 0, 1, \ldots, 6 \). Summing the real parts corresponding to the angles will let us express the cosine terms in terms of the roots. For the angle \( \frac{2\pi}{7} \), \( \frac{4\pi}{7} \), and \( \frac{6\pi}{7} \), notice that they are symmetric with respect to the unit circle. Adding these cosines effectively sums up three roots from the complex plane, giving a neat result that aligns with symmetry characteristics. This summation can also be derived from properties of Chebyshev polynomials or via a direct polynomial approach in trigonometric terms, ultimately leading to the conclusion that the sum equals \(-\frac{1}{2}\). For any triangular geometry or wave pattern applications, this result plays a significant role! It’s fascinating how trigonometric identities often find themselves in engineering and physics, showcasing the beautiful interconnectedness of mathematics and the real world!
