Find the \( x \)-intercept(s) and \( y \)-intercept(s), of the graph of the following, \[ x^{2}+y-25=0 \] If there is more than one answer, separate them with commas, Click on "None" if applicable. \( x \)-intercept(s):

To find the \( x \)-intercept(s), set \( y = 0 \) in the equation \( x^{2} + y - 25 = 0 \). This gives us: \[ x^{2} - 25 = 0 \] Solving for \( x \), we factor it as: \[ (x - 5)(x + 5) = 0 \] Thus, \( x = 5 \) and \( x = -5 \). So, the \( x \)-intercept(s) are \( 5, -5 \). Now, to find the \( y \)-intercept(s), set \( x = 0 \) in the original equation. This gives: \[ 0^{2} + y - 25 = 0 \] \[ y = 25 \] So, the \( y \)-intercept is \( 25 \). In summary, the \( x \)-intercept(s): \( 5, -5 \) and \( y \)-intercept(s): \( 25 \).