P. Required informotion Particle \( A \) has a mass of 5.50 g and particle \( B \) has a mass of 240 g . Particle \( A \) is located at the origin and particle \( B \) is at the point \( (x, y)=(750 \mathrm{~cm}, 220 \mathrm{~cm}) \). What is the \( x \) component of the center of mass? \( \square \mathrm{cm} \)

To find the \( x \) component of the center of mass (CM) of the two particles, we can use the formula: \[ x_{CM} = \frac{m_A x_A + m_B x_B}{m_A + m_B} \] Where: - \( m_A = 5.50 \, \text{g} \) - \( m_B = 240 \, \text{g} \) - \( x_A = 0 \, \text{cm} \) (since particle A is at the origin) - \( x_B = 750 \, \text{cm} \) Substituting the values into the formula: \[ x_{CM} = \frac{(5.50 \, \text{g} \cdot 0 \, \text{cm}) + (240 \, \text{g} \cdot 750 \, \text{cm})}{5.50 \, \text{g} + 240 \, \text{g}} \] Calculating the numerator: \[ = 0 + 180000 \, \text{g cm} = 180000 \, \text{g cm} \] Calculating the denominator: \[ = 5.50 \, \text{g} + 240 \, \text{g} = 245.50 \, \text{g} \] Now, dividing them: \[ x_{CM} = \frac{180000 \, \text{g cm}}{245.50 \, \text{g}} \approx 732.60 \, \text{cm} \] Thus, the \( x \) component of the center of mass is approximately \( 732.60 \, \text{cm} \).