Use a model for body surface area, \( B S A \), such that \( B S A=\sqrt{\frac{w h}{3600}} \), where \( w= \) weight in kg and \( h= \) height in cm . Find the weight of a \( 178-\mathrm{cm} \) male to the nearest kg whose \( B S A=2.6 \). \( \begin{array}{l}\text { kg }\end{array} \)

To find the weight \( w \) of a male who is 178 cm tall with a body surface area (BSA) of 2.6, we can use the given formula: \[ BSA = \sqrt{\frac{w h}{3600}} \] Plugging in the values we know, we have: \[ 2.6 = \sqrt{\frac{w \cdot 178}{3600}} \] Now, let's square both sides to eliminate the square root: \[ (2.6)^2 = \frac{w \cdot 178}{3600} \] Calculating \( (2.6)^2 \): \[ 6.76 = \frac{w \cdot 178}{3600} \] Next, we can multiply both sides by 3600 to isolate \( w \): \[ 6.76 \cdot 3600 = w \cdot 178 \] Calculating \( 6.76 \cdot 3600 \): \[ 24336 = w \cdot 178 \] Finally, divide both sides by 178 to find \( w \): \[ w = \frac{24336}{178} \approx 136.7 \] Rounding to the nearest kg, the weight is: \[ w \approx 137 \, \text{kg} \] So, the weight of the male whose BSA is 2.6 and height is 178 cm is approximately \( 137 \, \text{kg} \).