Find the value of \( x \) from each of the following. \( \begin{array}{lll}\text { (a) } x+5=8 & \text { (b) } 2-x=3 & \text { (c) } \frac{x}{3}=-2 \\ \text { (d) } \frac{15}{x}=5 & \text { (e) } 2 x=8 & \text { (f) } 16=4 x \\ \text { (g) } \frac{x}{3}=\frac{2}{9} & \text { (h) } \frac{x}{5}=\frac{1}{2} & \text { (i) } \frac{x+2}{12}=1 \\ \text { section } B & \end{array} \)

To solve each of these equations for \( x \), let's break them down one by one: (a) \( x + 5 = 8 \) Subtracting 5 from both sides, we get \( x = 8 - 5 \) which simplifies to \( x = 3 \). (b) \( 2 - x = 3 \) Rearranging gives \( -x = 3 - 2 \), leading to \( -x = 1 \), or \( x = -1 \). (c) \( \frac{x}{3} = -2 \) Multiplying both sides by 3 results in \( x = -2 \times 3 \), so \( x = -6 \). (d) \( \frac{15}{x} = 5 \) Multiplying both sides by \( x \) gives \( 15 = 5x \). Dividing by 5 leads to \( x = 3 \). (e) \( 2x = 8 \) Dividing both sides by 2 gives \( x = \frac{8}{2} \), so \( x = 4 \). (f) \( 16 = 4x \) Dividing both sides by 4 results in \( x = 4 \). (g) \( \frac{x}{3} = \frac{2}{9} \) Multiplying both sides by 3 gives \( x = \frac{2}{9} \times 3 \), simplifying to \( x = \frac{2}{3} \). (h) \( \frac{x}{5} = \frac{1}{2} \) Multiplying both sides by 5 results in \( x = 5 \times \frac{1}{2} \), so \( x = \frac{5}{2} \) or 2.5. (i) \( \frac{x+2}{12} = 1 \) Multiplying both sides by 12 gives \( x + 2 = 12 \). Subtracting 2 leads to \( x = 10 \). Summarizing the solutions: - (a) \( x = 3 \) - (b) \( x = -1 \) - (c) \( x = -6 \) - (d) \( x = 3 \) - (e) \( x = 4 \) - (f) \( x = 4 \) - (g) \( x = \frac{2}{3} \) - (h) \( x = \frac{5}{2} \) - (i) \( x = 10 \)