Length of court \( =30,5 \mathrm{~m} \) Width of court \( =15,25 \mathrm{~m} \) Radius of semicircle \( =4,9 \mathrm{~m} \) Area of centre circle \( =0,64 \mathrm{~m}^{2} \) -alculate the circumference of the centre circle

1. We start with the area of the centre circle given by \[ A = \pi r^2 = 0.64 \text{ m}^2. \] 2. Solve for the radius \(r\): \[ r = \sqrt{\frac{A}{\pi}} = \sqrt{\frac{0.64}{\pi}}. \] 3. The circumference \(C\) of a circle is \[ C = 2\pi r. \] Substitute for \(r\): \[ C = 2\pi \sqrt{\frac{0.64}{\pi}}. \] 4. Simplify the expression: \[ C = 2\pi \sqrt{\frac{0.64}{\pi}} = 2\pi \frac{\sqrt{0.64}}{\sqrt{\pi}} = \frac{2\pi \cdot 0.8}{\sqrt{\pi}} = 1.6 \sqrt{\pi}. \] 5. Evaluating numerically (with \(\sqrt{\pi} \approx 1.772\)): \[ C \approx 1.6 \times 1.772 \approx 2.835 \text{ m}. \] Thus, the circumference of the centre circle is approximately \(2.84 \text{ m}\).