Given the function $$ f(t)=(t-7)(t+4)(t-1) $$ its $$ f $$-intercept is its $$ t $$-intercepts are

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1. To find the $$ f $$-intercept (i.e., the $$ y $$-intercept), evaluate $$ f(t) $$ at $$ t = 0 $$:
   $$
   f(0) = (0-7)(0+4)(0-1) = (-7)(4)(-1) = 28
   $$
   Thus, the $$ f $$-intercept is $$ 28 $$.

2. The $$ t $$-intercepts are found by setting $$ f(t) = 0 $$:
   $$
   (t-7)(t+4)(t-1) = 0
   $$
   Solve each factor:
   - $$ t - 7 = 0 $$ gives $$ t = 7 $$
   - $$ t + 4 = 0 $$ gives $$ t = -4 $$
   - $$ t - 1 = 0 $$ gives $$ t = 1 $$

Thus, the $$ t $$-intercepts are $$ t = 7 $$, $$ t = -4 $$, and $$ t = 1 $$.
The $$ f $$-intercept is 28, and the $$ t $$-intercepts are at $$ t = 7 $$, $$ t = -4 $$, and $$ t = 1 $$.

Given the function \( f(t)=(t-7)(t+4)(t-1) \) its \( f \)-intercept is its \( t \)-intercepts are

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