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The graph shows distance in feet as a function of time in seconds. Write an equation for the function and describe a situation that it could represent. Include the initial value and rate of change for the function and what each of these values represents in this situation.

Ask by Ayala Ross. in the United States
Mar 11,2025

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The equation for the function is \( d(t) = 5t + 10 \). This represents a situation where someone starts 10 feet away from a reference point and moves away at a constant speed of 5 feet per second.

Solución

To create an equation for a function that represents distance as a function of time, we can use the linear equation format: \[ d(t) = mt + b \] where: - \(d(t)\) is the distance in feet, - \(m\) is the rate of change (slope) in feet per second, - \(t\) is the time in seconds, - \(b\) is the initial value (y-intercept), which represents the initial distance at \(t = 0\). ### Step 1: Identify the Initial Value and Rate of Change 1. **Initial Value (\(b\))**: This is the distance at \(t = 0\). For example, if the graph shows that the distance is 10 feet when \(t = 0\), then \(b = 10\). 2. **Rate of Change (\(m\))**: This is the slope of the line, representing how much distance changes per unit of time. For instance, if the graph indicates that the distance increases by 5 feet every second, then \(m = 5\). ### Step 2: Write the Equation Using the values identified: - If \(b = 10\) (initial distance) and \(m = 5\) (rate of change), the equation would be: \[ d(t) = 5t + 10 \] ### Step 3: Describe a Situation This equation could represent a scenario where a person is walking away from a starting point. For example, imagine a person starts walking from a point 10 feet away from a reference point (like a starting line) and walks at a constant speed of 5 feet per second. ### Summary of Values - **Initial Value (\(b\))**: 10 feet - This represents the starting distance from the reference point. - **Rate of Change (\(m\))**: 5 feet/second - This indicates the speed at which the person is walking away from the starting point. In conclusion, the function \(d(t) = 5t + 10\) describes the distance of a person walking away from a starting point at a constant speed, starting from 10 feet away.

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Imagine you're watching a rocket launch! The initial value in this scenario represents the height of the rocket at the start, typically 0 feet if it's on the ground. As the rocket launches, the distance it travels over time reflects its ascent. The rate of change shows how quickly it climbs, measured in feet per second. If the rocket ascends at a steady rate, let's say 50 feet per second, the equation could look like \(d(t) = 50t\), where \(d(t)\) is the distance in feet and \(t\) is time in seconds. This equation perfectly captures the exciting journey of the rocket breaking away from Earth's grasp! Now, picture a baseball being thrown instead. Here, the initial value might be 0 feet, just like the rocket. The rate of change would indicate how fast the ball is moving upward, let’s say 60 feet per second for the first few seconds before it starts to fall back down due to gravity. The equation could then illustrate its trajectory, showing how the ball ascends before reaching its peak and descending back to home plate. It's all about the thrill of the toss!

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