(b) Marcus invests in an account that pays per year simpie in account for 6 years.
He leaves the money in the
At the end of 6 years there is in the account.

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Mar 22,2025

Question

(b) Marcus invests in an account that pays $$ 1.8 \% $$ per year simpie in account for 6 years. He leaves the money in the At the end of 6 years there is $$ \$ 1385 $$ in the account.

UpStudy AI · Accepted Answer

**Step 1: Write the formula for simple interest**  
The amount $$ A $$ after $$ t $$ years with a principal $$ P $$ and an annual simple interest rate $$ r $$ is given by:  
$$
A = P(1 + rt)
$$

**Step 2: Substitute the given values into the formula**  
Here,  
- $$ A = 1385 $$
- $$ r = 0.018 $$ (since $$ 1.8\% = 0.018 $$)
- $$ t = 6 $$

Substitute these into the formula:  
$$
1385 = P(1 + 0.018 \times 6)
$$

**Step 3: Simplify the equation**  
Calculate $$ 0.018 \times 6 $$:  
$$
0.018 \times 6 = 0.108
$$  
Thus,  
$$
1385 = P(1 + 0.108) = P(1.108)
$$

**Step 4: Solve for $$ P $$**  
To isolate $$ P $$, divide both sides of the equation by $$ 1.108 $$:  
$$
P = \frac{1385}{1.108}
$$

**Step 5: Calculate the value of $$ P $$**  
Perform the division:  
$$
P = 1250
$$

**Final Answer:**  
Marcus's initial investment was $$ \$1250 $$.
Marcus initially invested \$1,250.

(b) Marcus invests in an account that pays per year simpie in account for 6 years.
He leaves the money in the
At the end of 6 years there is in the account.

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(b) Marcus invests in an account that pays per year simpie in account for 6 years. He leaves the money in the At the end of 6 years there is in the account.