Given the function \( f \), find \( f(-3), f(3), f(-a),-f(a), f(a+h) \) \[ \begin{array}{l}f(x)=2 x-7 \\ f(-3)= \\ f(3)= \\ f(-a)= \\ -f(a)= \\ f(a+h)= \\ \end{array} \]
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Let's evaluate the function \( f(x) = 2x - 7 \) for the different inputs. First, we'll find \( f(-3) \): \[ f(-3) = 2(-3) - 7 = -6 - 7 = -13 \] Next, we compute \( f(3) \): \[ f(3) = 2(3) - 7 = 6 - 7 = -1 \] Now, we calculate \( f(-a) \): \[ f(-a) = 2(-a) - 7 = -2a - 7 \] For \( -f(a) \): \[ f(a) = 2a - 7, \quad \text{so} \quad -f(a) = -(2a - 7) = -2a + 7 \] Lastly, we find \( f(a+h) \): \[ f(a+h) = 2(a+h) - 7 = 2a + 2h - 7 \] In summary: \[ f(-3) = -13, \quad f(3) = -1, \quad f(-a) = -2a - 7, \quad -f(a) = -2a + 7, \quad f(a+h) = 2a + 2h - 7 \]
