\( \begin{array}{ll}\text { 2) } \frac{65}{5}=\square & \text { 3) } \frac{51}{3}=\square \\ \text { 5) } \frac{72}{4}=\square & \text { 6) } \frac{94}{2}=\square \\ \text { 8) } \frac{87}{3}=\square \\ \text { 14) } \frac{50}{4}=\square \\ \text { 17) } \frac{78}{6}=\square\end{array} \)

**2) \(\frac{65}{5}\)** We divide 65 by 5. Since \(5 \times 13 = 65\), \[ \frac{65}{5}=13. \] **3) \(\frac{51}{3}\)** We divide 51 by 3. Since \(3 \times 17 = 51\), \[ \frac{51}{3}=17. \] **5) \(\frac{72}{4}\)** We divide 72 by 4. Since \(4 \times 18 = 72\), \[ \frac{72}{4}=18. \] **6) \(\frac{94}{2}\)** We divide 94 by 2. Since \(2 \times 47 = 94\), \[ \frac{94}{2}=47. \] **8) \(\frac{87}{3}\)** We divide 87 by 3. Since \(3 \times 29 = 87\), \[ \frac{87}{3}=29. \] **14) \(\frac{50}{4}\)** We divide 50 by 4. \(4\) goes into \(50\) a non-integer number of times. In fact, \[ \frac{50}{4}=12.5, \] or as an improper fraction, \[ \frac{50}{4}=\frac{25}{2}. \] **17) \(\frac{78}{6}\)** We divide 78 by 6. Since \(6 \times 13 = 78\), \[ \frac{78}{6}=13. \]