8. Multiply the numbers in the indicated bases: \( 3214_{5} \times 24_{5} \)
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First, let's convert the numbers from base 5 to base 10 to make multiplication easier. For \( 3214_{5} \): \[ 3 \times 5^3 + 2 \times 5^2 + 1 \times 5^1 + 4 \times 5^0 = 3 \times 125 + 2 \times 25 + 1 \times 5 + 4 \times 1 = 375 + 50 + 5 + 4 = 434_{10} \] For \( 24_{5} \): \[ 2 \times 5^1 + 4 \times 5^0 = 2 \times 5 + 4 \times 1 = 10 + 4 = 14_{10} \] Now we can multiply these two decimal numbers: \[ 434_{10} \times 14_{10} = 6076_{10} \] Next, we convert \( 6076_{10} \) back to base 5. We will do this by continually dividing by 5 and keeping track of the remainders. 1. \( 6076 \div 5 = 1215 \) remainder \( 1 \) 2. \( 1215 \div 5 = 243 \) remainder \( 0 \) 3. \( 243 \div 5 = 48 \) remainder \( 3 \) 4. \( 48 \div 5 = 9 \) remainder \( 3 \) 5. \( 9 \div 5 = 1 \) remainder \( 4 \) 6. \( 1 \div 5 = 0 \) remainder \( 1 \) Now, reading the remainders from bottom to top, we get \( 143301_{5} \). Therefore, the product \( 3214_{5} \times 24_{5} \) is: \[ \boxed{143301_{5}} \]
