stion 4 of 7 , Step 1 of 1 Isider all four-digit numbers that can be made from the digits \( 0-8 \) (assume that numbers cannot start with 0 ). What is the probability of choosing a randam nu n this group that is greater than 2000 ? Enter a fraction or round your answer to 4 decimal places, if necessary.
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Beyond the Answer
To find the probability of choosing a random four-digit number greater than 2000 made from the digits 0-8, we first need to determine the total number of valid four-digit numbers. 1. **Total Four-Digit Numbers**: The first digit can be any from 1 to 8 (since it cannot be 0), giving us 8 options. The remaining three digits can be from 0 to 8, giving us 9 options each. Therefore, the total number of four-digit numbers is: \[ 8 \times 9 \times 9 \times 9 = 5832 \] 2. **Numbers Greater than 2000**: For a number to be greater than 2000, the first digit must be either 2, 3, 4, 5, 6, 7, or 8. This gives us 7 options for the first digit. The remaining three digits can still be from 0 to 8, giving us 9 options each. Thus, the total numbers greater than 2000 are: \[ 7 \times 9 \times 9 \times 9 = 5103 \] 3. **Probability Calculation**: The probability of choosing a number greater than 2000 is calculated by dividing the number of favorable outcomes by the total outcomes: \[ P(\text{greater than 2000}) = \frac{5103}{5832} \] 4. **Simplifying the Fraction**: To simplify \( \frac{5103}{5832} \), we can divide both the numerator and denominator by their greatest common divisor, which is 3: \[ \frac{5103 \div 3}{5832 \div 3} = \frac{1701}{1944} \] Since 1701 and 1944 have no other common factors, this is in simplest form. Thus, the probability of randomly choosing a four-digit number from this set that is greater than 2000 is \( \frac{1701}{1944} \) or approximately 0.8756 when rounded to four decimal places.
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